Answer:
As Per Provided Information
- Mass of car is 1600 Kg
- Initial velocity 20 m/s
- Final velocity 0m/s
we have been asked to determine the change in momentum .
Formula Used
[tex] \bf\Delta \: p = m \: \times \Delta \:v[/tex]
Put the given value we obtain
[tex] \rm \qquad \dashrightarrow \Delta \: p \: = 1600 \times (0 - 20) \\ \\ \\ \rm \qquad \dashrightarrow \Delta \: p \: = 1600 \times ( - 20) \\ \\ \\ \rm \qquad \dashrightarrow \Delta \: p \: = - 32000 \: kgm {s}^{ - 1} [/tex]
Hence,
- Change in momentum is -32000Kgm/s .
So, correct option is (a) -32000 Kgm/s.