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A recent study of high school students shows the percentage of females and males who took advanced math courses. A simple random sample of high school students was interviewed. The students were asked whether they had taken an advanced math course. Of the 150 females, 53 answered yes, as did 89 of the 275 males.

Part A: Construct and interpret a 98% confidence interval for the difference in population proportions of females and males who took advanced math courses. Be sure to state the parameter, check conditions, perform calculations, and make conclusion(s). (8 points)

Part B: Does your interval from part A give convincing evidence of a difference between the population proportions? Explain. (2 points)

A. The 98% confidence interval is (-0.082, 0.141), and it means that we are 98% sure that the true difference of the population proportions are in this interval.

B. Since 0 is part of the confidence interval, it does not give convincing evidence of a difference between the population proportions.

What is the mean and the standard error for the distribution of differences?

For each sample, they are given by:

[tex]p_F = \frac{53}{150} = 0.3533, s_F = \sqrt{\frac{0.3533(0.6467)}{150}} = 0.039[/tex]

[tex]p_M = \frac{89}{275} = 0.3236, s_M = \sqrt{\frac{0.3236(0.6764)}{275}} = 0.0282[/tex]

Hence, for the distribution of differences:

[tex]p = p_F - p_M = 0.3533 - 0.3236 = 0.0297[/tex]

[tex]s = \sqrt{s_F^2 + s_M^2} = \sqrt{0.039^2 + 0.0282^2} = 0.048[/tex]

What is the confidence interval:

It is given by:

[tex]p \pm zs[/tex]

98% confidence interval, hence, using a z-distribution calculator, the critical value is of z = 2.327.

Then:

[tex]p - zs = 0.0297 - 2.327(0.048) = -0.082[/tex]

[tex]p + zs = 0.0297 + 2.327(0.048) = 0.141[/tex]

The 98% confidence interval is (-0.082, 0.141), and it means that we are 98% sure that the true difference of the population proportions are in this interval.

Item b:

Since 0 is part of the confidence interval, it does not give convincing evidence of a difference between the population proportions.

To learn more about the z-distribution, you can check https://brainly.com/question/25890103