A cast iron pipe used as a water main for a home has an outer diameter of 11 in. If the pipe has a thickness of 0. 25 in, what volume of iron does 30 in of pipe contain? Answer in cubic inches. Round your answer to the nearest hundredth if necessary

Respuesta :

The volume of the cast iron pipe will be equal to 253.29 in³.

Volume of Hollow Cylinder

The volume of hollow cylinder formula is: V = π (R² -r²)h, where:

R= radius of outer diameter (OD)

r=  radius of inner diameter (ID)

h= height

First you need to find the radius of this cylinder.

1- Find r - radius of inner diameter

For this, you should apply the formula: ID=OD-2wt, where:

ID= inner diameter = ?

OD= outer diameter= 11 in

wt= thickness= 0.25 in

Then, ID=OD-2wt= 11-2*0.25=11-0.5=10.5 in.

If inner diameter is equal to 10.5 in, the inner radius will be [tex]\frac{10.5}{2} =5.25[/tex] in.

2- Find R - radius of outer diameter

If outer diameter is equal to 11 in, the inner radius will be [tex]\frac{11}{2} =5.5[/tex] in.

3- Find the volume of hollow cylinder

V = π (R² -r²)h

V = π (5.5² -5.25²)30

V=30π(30.25-27.5625)

V=30π(2.6875)

V=80.625π

V=253.29 in³

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