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To prove that ΔDEF ≅ ΔDGF by SAS, what additional information is needed?

(A) ∠DEF ≅ ∠ DGF
(B) ∠DFE ≅ ∠ DFG
(C) DE ≅ DG
(D) DG ≅ GF

To prove that ΔDEF ΔDGF by SAS what additional information is needed A DEF DGF B DFE DFG C DE DG D DG GF class=

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Answer:

(B) ∠DFE ≅ ∠ DFG

Step-by-step explanation:

triangle is congruent by sas

1. gf = ef ( shown in figure) side

2. df = fd ( common) side

3rd is additional information

we got both the side and sas congruency must have two sides and one angle . and that anngle must be in between the two sides so

3. ∠DFE ≅ ∠ DFG

Answer:  (B) ∠DFE ≅ ∠ DFG

Explanation:

SAS = side angle side

The tickmarks show that EF = FG which forms one "S" of "SAS".

The other "S" is the fact that FD = FD due to the reflexive property.

The missing info we need is ∠DFE ≅ ∠ DFG, both of those angles are between the sides mentioned. The order is important.

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