The volume of water needed to dilute the solution to obtain a 0.25 M NaCl solution is 75 mL
Data obtained from the question
- Volume of stock solution (V₁) = 25 mL
- Molarity of stock solution (M₁) = 1 M
- Molarity of diluted solution (M₂) = 0.250 M
How to determine the volume of diluted solution
- Volume of stock solution (V₁) = 25 mL
- Molarity of stock solution (M₁) = 1 M
- Molarity of diluted solution (M₂) = 0.250 M
- Volume of diluted solution (V₂) =?
M₁V₁ = M₂V₂
1 × 25 = 0.250 × V₂
25 = 0.25 × V₂
Divide both side by 0.25
V₂ = 25 / 0.25
V₂ = 100 mL
How to determine the volume of water
- Volume of stock solution (V₁) = 25 mL
- Volume of diluted solution (V₂) = 100 mL
Volume of water = V₂ – V₁
Volume of water = 100 – 25
Volume of water = 75 mL
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