Answer:
s ≈ 35.8 m
Explanation:
Let's apply the uniform acceleration equation to find the vertical height travelled after 2.7 seconds.
[tex]s = ut + \frac{1}{2}at^2[/tex]
s = distance travelled
u = initial vertical velocity
t = time taken
a = gravitational acceleration
The gun is fired horizontally, hence there is no initial vertical velocity.
[tex]s = 0(2.7) + \frac{1}{2}(9.81)(2.7)^2[/tex]
[tex]s = 35.75745 m[/tex]
s ≈ 35.8 m
