Respuesta :
0.53 is the probability that he chooses two different types of biscuits.
explanation:
- digestive biscuits: 7
- chocolate biscuits: 5
- total biscuits: 12
probability:
[tex]\rightarrow \sf \dfrac{7}{12} *\dfrac{5}{11} + \dfrac{5}{12} * \dfrac{7}{11}[/tex]
[tex]\rightarrow \sf \dfrac{35}{66}[/tex]
[tex]\rightarrow \sf 0.53[/tex]
Answer:
35/132 = 0.27 (nearest hundredth)
Step-by-step explanation:
Total number of biscuits = 12
Number of digestives = 7
Number of chocolate biscuits = 5
The probability of the first biscuit being a digestive is 7/12
As the first biscuit was not replaced, the total number of biscuits is now 11.
So the probability of the second biscuit being chocolate is 5/11
Therefore, the probability of the first biscuit being a digestive AND the second being chocolate is:
[tex]\dfrac{7}{12}\times\dfrac{5}{11}=\dfrac{35}{132}[/tex]
Similarly,
The probability of the first biscuit being chocolate is 5/12
As the first biscuit was not replaced, the total number of biscuits is now 11.
So the probability of the second biscuit being a digestive is 7/11
Therefore, the probability of the first biscuit being chocolate AND the second being a digestive is:
[tex]\dfrac{5}{12}\times\dfrac{7}{11}=\dfrac{35}{132}[/tex]