Steve has 12 biscuits in a tin.
There are 7 digestive and 5 chocolate biscuits.
Steve takes two biscuits at random from the tin.
Work out the probability that he chooses two different types of biscuits.

Respuesta :

0.53 is the probability that he chooses two different types of biscuits.

explanation:

  • digestive biscuits: 7
  • chocolate biscuits: 5
  • total biscuits: 12

probability:

[tex]\rightarrow \sf \dfrac{7}{12} *\dfrac{5}{11} + \dfrac{5}{12} * \dfrac{7}{11}[/tex]

[tex]\rightarrow \sf \dfrac{35}{66}[/tex]

[tex]\rightarrow \sf 0.53[/tex]

Answer:

35/132 = 0.27 (nearest hundredth)

Step-by-step explanation:

Total number of biscuits = 12

Number of digestives = 7

Number of chocolate biscuits = 5

The probability of the first biscuit being a digestive is 7/12

As the first biscuit was not replaced, the total number of biscuits is now 11.

So the probability of the second biscuit being chocolate is 5/11

Therefore, the probability of the first biscuit being a digestive AND the second being chocolate is:

[tex]\dfrac{7}{12}\times\dfrac{5}{11}=\dfrac{35}{132}[/tex]

Similarly,

The probability of the first biscuit being chocolate is 5/12

As the first biscuit was not replaced, the total number of biscuits is now 11.

So the probability of the second biscuit being a digestive is 7/11

Therefore, the probability of the first biscuit being chocolate AND the second being a digestive is:

[tex]\dfrac{5}{12}\times\dfrac{7}{11}=\dfrac{35}{132}[/tex]

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