Answer:
Slope-intercept form:
[tex]y=\dfrac12x+\dfrac{13}2[/tex]
Standard form:
[tex]x-2y=-13[/tex]
Step-by-step explanation:
Point-slope form of a linear equation: [tex]y-y_1=m(x-x_1)[/tex]
(where [tex]m[/tex] is the slope and [tex](x_1,y_1)[/tex] is the point)
Given:
- [tex]m=\dfrac12[/tex]
- [tex](x_1,y_1)=(-5,4)[/tex]
Substituting these values into the point-slope formula:
[tex]\implies y-4=\dfrac12(x+5)[/tex]
[tex]\implies y-4=\dfrac12x+\dfrac52[/tex]
[tex]\implies y=\dfrac12x+\dfrac{13}2[/tex]
Slope-intercept form:
[tex]y=\dfrac12x+\dfrac{13}2[/tex]
Standard form:
[tex]x-2y=-13[/tex]
