The system of equations that model this situation are [tex]h = -16t^{2}+15t +6[/tex] and [tex]h = 3t +10[/tex].
As we know,
Projectile motion formula,
[tex]h = -16t^{2}+vt +h_{0}[/tex].....(1)
Where, t = time since the measuring tape was thrown.
h = height in feet above the ground.
What is a projectile motion?
Projectile motion is a form of motion experienced by an object or particle that is projected near the Earth's surface and moves along a curved path under the action of gravity only.
It is given that:
v =15 feet/sec
hâ‚€ = 6 feet
So, (1) will become,
[tex]h = -16t^{2}+15t +6[/tex]
Also, h = distance of worker's arm from the ground + speed of bucket * time(t)
[tex]h = 3t +10[/tex]
Therefore, the system of equations that model this situation are [tex]h = -16t^{2}+15t +6[/tex] and [tex]h = 3t +10[/tex].
To get more about projectile motion visit:
https://brainly.com/question/24216590
