Write the equation of the line, in slope intercept form, that is perpendicular to 3x+6y=18 passing through the point (-4,2). Show your work.

Respuesta :

Answer:

y = 2x + 10

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

given

3x + 6y = 18 ( subtract 3x from both sides )

6y = - 3x + 18 ( divide terms by 6 )

y = - [tex]\frac{1}{2}[/tex] x + 3 ← in slope- intercept form

with slope m = - [tex]\frac{1}{2}[/tex]

given a line with slope m then the slope of a line perpendicular to it is

[tex]m_{perpendicular}[/tex] = - [tex]\frac{1}{m}[/tex] = - [tex]\frac{1}{-\frac{1}{2} }[/tex] = 2 , then

y = 2x + c ← is the partial equation

to find c substitute (- 4, 2 ) into the partial equation

2 = - 8 + c ⇒ c = 2 + 8 = 10

y = 2x + 10 ← equation of perpendicular line

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