Calculate the mass of 5.00x10^25 atoms of AgNO3

Answer:
1.41 x 10 ^4
Explanation:
change atoms to mol then to gram
5 x 10^25 atoms of AgNO3 [tex]\frac{1mol AgNO3}{6.023 x 10 ^23}[/tex][tex]\frac{169.91g}{1mol AgNO3}[/tex]
= 141.05g x 10^2 move the decimal over if you are doing sig fig 1.41 x 10^4
change atoms to mol using Avogadro's number 6.023 x 10^23 then mol to gram using the molar mass of AgNO3.