How fast was a driver going if the car left skid marks that were 80 feet long on dry concrete? (The coefficient of friction is 1.02)?

73 mph

38 mph

49 mph​

Respuesta :

The speed of the car with skid marks of 80 feet long on dry concrete is 51 mph

Speed

  • v = √32fd

Skid marks

A skid mark made by a car is the mark a tire makes when a vehicle wheel stops rolling and slides or spins on the surface of the road. This is simply the marks made by a car tire when the brake is held. 

where

f = coefficient of friction determined by when the car was skidding.

d = skid mark length

v = speed

Therefore,

v = √ 32 × 1.02 × 80

v = √ 2611.2

v = 51.0999021525

v = 51 mph

learn more on skid marks here: https://brainly.com/question/21734785

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