The margin of error for the population mean for the 90% confidence level is 1.10.
The margin of error is a statistic that expresses how much random sampling error there is in a survey's results. The wider the margin of error, the less confident one should be that a poll result reflects the outcome of a population-wide survey.
It is given by the formula:
[tex]MOE_y=Z_y\times \sqrt{\dfrac{\sigma^2}{n} }[/tex]
As the mean is given to us is 71 beats and the standard deviation is 6 beats, therefore, the margin of error for 90% confidence level can be written as,
[tex]MOE_y=Z_y\times \sqrt{\dfrac{\sigma^2}{n} }[/tex]
[tex]MOE_y=1.645\times \sqrt{\dfrac{\ 6^2}{80} }[/tex]
[tex]MOE_y= 1.645\times \sqrt{\dfrac{36}{80} }[/tex]
[tex]MOE_y= 1.10[/tex]
Thus the margin of error for the population mean for the 90% confidence level is 1.10.
To know more about Z- score follow
https://brainly.com/question/25800303
