contestada

The City of Jacksonville Property Appraisers' Office has calculated that the average sized home in Jacksonville is 1,390 square feet. All the information fits a normal distribution with a standard deviation of 370 square feet. What percentage of homes in Jacksonville are less than 1,760 square feet? Complete the bell curve in order to find this percentage.


A. 83. 85%

B. 84%

C. 95%

D. 99. 7%

Respuesta :

raphealnwobi

The percentage of homes in Jacksonville are less than 1,760 square feet is 84%.

What is z score?

Z score is used to determine by how many standard deviations the raw score is above or below the mean. It is given by:

z = (raw score - mean)/standard deviation

Given that:

Mean = 1390 ft², standard deviation = 370 ft²

For x < 1760:

z = (1760 - 1390) / 370 = 1

P(x < 1760) = P(z < 1) = 84%

The percentage of homes in Jacksonville are less than 1,760 square feet is 84%.

Find out more on z score at: https://brainly.com/question/25638875

ACCESS MORE
ACCESS MORE
ACCESS MORE
ACCESS MORE

Otras preguntas