Answer: [tex]24.5\times 10^{23}atoms[/tex]
Explanation:
According to avogadro's law, 1 mole of every substance weighs equal to its molecular mass and contains avogadro's number [tex]6.023\times 10^{23}[/tex] of particles.
To calculate the number of moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar Mass}}=\frac{163g}{40g/mol}=4.075moles[/tex]
1 mole of calcium contains = [tex]6.023\times 10^{23}atoms[/tex]
Thus 4.075 moles of calcium contains = [tex]\frac{6.023\times 10^{23}}{1}\times 4.075 =24.5\times 10^{23}atoms[/tex]
Thus there are [tex]24.5\times 10^{23}atoms[/tex] in 163 g of calcium.
