Let
x-------> the first odd number
x+2----> the second consecutive odd number
x+4-----> the third consecutive odd number
x+6-----> the fourth consecutive odd number
x+8-----> the fifth consecutive odd number
we know that
[tex]x+(x+2)+(x+4)+(x+6)+(x+8)=145[/tex]
Solve for x
[tex]5x+20=145[/tex]
[tex]5x=145-20[/tex]
[tex]5x=125[/tex]
[tex]x=25[/tex]
so
The sequence is
[tex]25,27,29,31,33[/tex]
therefore
the answer is
The third number in the sequence is the number [tex]29[/tex]
