Choose the point-slope form of the equation below that represents the line that passes through the point (6, −3) and has a slope of one half.

y − 6 = one half(x + 3)
y = one halfx − 6
y + 3 = one half(x − 6)
x − 2y = 12

Respuesta :

The answer is y+3=1/2(x-6). Btw, do you do k12?

Answer:

[tex]\text{The point slope form is }y+3=\frac{1}{2}(x-6)[/tex]  

Step-by-step explanation:

[tex]\text{Given that the line line passes through the point (6,-3) and has slope }\frac{1}{2}[/tex]

we have to find the equation of line in the point-slope form.

[tex]\text{The equation of line passing through the point (x',y') and has slope m is }[/tex]

[tex]y-y'=m(x-x')[/tex]

[tex]\text{Passing point=(x',y')=(6,-3)}[/tex]

[tex]Slope=m=\frac{1}{2}[/tex]

The equation is

[tex]y-(-3)=\frac{1}{2}(x-6)[/tex]

[tex]y+3=\frac{1}{2}(x-6)[/tex]

which is required point-slope form.

Option 3 is correct.

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