Answer:
[tex]\text{The point slope form is }y+3=\frac{1}{2}(x-6)[/tex]
Step-by-step explanation:
[tex]\text{Given that the line line passes through the point (6,-3) and has slope }\frac{1}{2}[/tex]
we have to find the equation of line in the point-slope form.
[tex]\text{The equation of line passing through the point (x',y') and has slope m is }[/tex]
[tex]y-y'=m(x-x')[/tex]
[tex]\text{Passing point=(x',y')=(6,-3)}[/tex]
[tex]Slope=m=\frac{1}{2}[/tex]
The equation is
[tex]y-(-3)=\frac{1}{2}(x-6)[/tex]
[tex]y+3=\frac{1}{2}(x-6)[/tex]
which is required point-slope form.
Option 3 is correct.