The volume of the container will be 0.45L.
What is Boyle's law?
This law states that the product of volume and its pressure is constant for any gas.
Given, the Volume 1 of container 6.0L
V2 =?
Pressure 1 is 150 kPa
Increased pressure 2 is 2 atm
Temperature is constant.
By Boyle's law:
P1V1 = P2V2
[tex]150 \times 6 = 2\times V2 = 450[/tex]
Thus, V2 = 0.45 L.
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