Respuesta :

Sine is opposite over hypotenuse so we'd have 7 over the square root of 130. The square root of 130 is 11.4017 approximately so you should have 7 over 11.4017 (you can leave out the one and the seven) Does this help you?
ThonyBossa

Answer:

0,61

Step-by-step explanation:

According trigonometry, we have the next relations

[tex]Sen \theta = \frac{side-opossite}{hypotenuse} [/tex]

In our case and according the picture, we have

[tex]Sen A = \frac{side-opossite}{hypotenuse} = \frac{7}{\sqrt{130}} [/tex]

[tex]Sen A = 0,61 [/tex]

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