Respuesta :

Abu99

Answer:

[tex] \frac{\sqrt[4]{3}}{ \sqrt[5]{3} } = \frac{ {3}^{ \frac{1}{4} } }{ {3}^{ \frac{1}{5} } } \\ = {3}^{ \frac{1}{4} - \frac{1}{5} } \\ = {3}^{ \frac{5}{20} - \frac{4}{20} } \\ = {3}^{ \frac{1}{20} } \: or \: \sqrt[20]{3} [/tex]

Answer:

[tex]\sqrt[20]{3}[/tex]

Step-by-step explanation:

Using the radical rule ([tex]\sqrt[x]{a}=a^{\frac{1}{x}[/tex]), we can rewrite the fraction:

(3^1/4)/(3^1/5)

Since we are dividing exponents with the same base, we can subtract the two exponents to get:

3^(1/4-1/5)

Convert both fractions to a base of 20:

[tex]\frac{1}{4}*\frac{5}{5}=\frac{5}{20}[/tex] (notice we can only multiply by a number of itself since it is essentially like multiplying the fraction by 1)

[tex]\frac{1}{5}*\frac{4}{4}=\frac{4}{20}[/tex]

Therefore we have:

3^(5/20-4/20)=3^(1/20)

Which again using the radical rule we can rewrite as:

[tex]\sqrt[20]{3}[/tex]

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