Answer:
[tex]\frac{4x-13}{x-4}[/tex]
Explanation:
→ [tex]\frac{4x+3}{x} + \frac{24}{2x^2 -8x}[/tex]
[ least common multiple ]
→ [tex]\frac{(4x+3)(2x^2 -8x)+24(x)}{x(2x^2 - 8x)}[/tex]
[ open the brackets ]
→ [tex]\frac{8x^3 -32x^2 +6x^2 -24x+24x}{x(2x^2 -8x)}[/tex]
[ simplify ]
→ [tex]\frac{8x^3 -26x^2 }{2x(x-4)}[/tex]
[ final answer ]
→ [tex]\frac{4x-13}{x-4}[/tex]
