Answer:
39.82693 kJ
Explanation:
Sensible heat is computed as follows:
Q = m*cp*ΔT
where Q is heat, m is mass, cp is heat capacity and ΔT is temperature change.
Latent heat transformation is computed as follows:
Q = m*λ
where λ is latent heat
water latent heat of fusion: 334 J/g
water latent heat of vaporization: 2260 J/g
First you have to heat ice from -12 °C to its melting point (0 °C) as follows:(this is a sensible heat transformation)
Q1 = m*cp*ΔT
Q1 = 13*2.09*(0 - (-12))
Q1 = 326.04 J = 0.32604 kJ
Then you have to melt the ice into water as follows:
(this is a latent heat transformation)
Q2 = m*λ
Q2 = 13*334
Q2 = 4342 J = 4.342 kJ
Next, you have to heat the water from 0 °C to its boiling point (100 °C) as follows:
(this is a sensible heat transformation)
Q3 = m*cp*ΔT
Q3 = 13*4.184*(100 - 0) (heat capacity of water: 4.184 J/(g °C))
Q3 = 5439.2 J = 5.4392 kJ
Then you have to evaporate the water into steam as follows:
(this is a latent heat transformation)
Q4 = m*λ
Q4 = 13*2260
Q4 = 29380 J = 29.38 kJ
Finally, you have to heat the steam from 100 °C to 113 °C as follows:
(this is a sensible heat transformation)
Q5 = m*cp*ΔT
Q5 = 13*2.01*(113 - 100)
Q5 = 339.69 J = 0.33969 kJ
Total heat, Q = Q1 + Q2 + Q3 + Q4 + Q5 = 0.32604 + 4.342 + 5.4392 + 29.38 + 0.33969 = 39.82693 kJ
