Respuesta :
The radio signal will take 0.0025 seconds to travel from a satellite to the surface of the Earth if the satellite is orbiting at a height of 7.5 x 10^6 meters.
Given,
Radio signals travel at a rate of 3 x 10^8 meters per second.
The satellite is orbiting at a height of 7.5 x 10^6 meters.
We need to find how many seconds will it take for a radio signal to travel from a satellite to the surface of the Earth.
We have,
Radio signals speed = 3 x 10^8 meters per second.
This means in one second it travels 3 x 10^8 meters.
1 second = 3 x 10^8 meters.
Height of the satellite = 7.5 x 10^6 meters.
The radio signal has to travel 7.5 x 10^6 meters to reach the surface of the earth from the satellite.
We need to find how many seconds for 7.5 x 10^6 meters.
We have,
3 x 10^8 meters = 1 second
Multiplying (7.5 x 10^6) / (3 x 10^8) on both sides
(7.5 x 10^6)/(3 x 10^8) x 3 x 10^8 meters = (7.5 x 10^6)/(3 x 10^8) x 1 second.
7.5 x 10^6 meters = (7.5/3) x 10^(6-8) seconds
= 2.5 x 10^-3 seconds
= 2.5 / 1000 seconds
= 0.0025 seconds
To travel 7.5 x 10^6 meters the radio signal will take 0.0025 seconds.
Thus the radio signal will take 0.0025 seconds to travel from a satellite to the surface of the Earth if the satellite is orbiting at a height of 7.5 x 10^6 meters.
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