Answer:
D.) x = 12, solution is extraneous
Step-by-step explanation:
We are given a equation
[tex]-4\times \sqrt{x-3}=12[/tex]
⇒ [tex]\sqrt{x-3}=-3[/tex]
on squaring both sides, we get
x-3=9
⇒ x=12
Putting x=12 in original equation gives
[tex]-4\times \sqrt{12-3}=12[/tex]
⇒ -4×3=12
which is not true
Hence, correct option is:
D.) x = 12solution is extraneous
