alisalameh
alisalameh
19-01-2017
Mathematics
contestada
indefinte integral of sec3xtan3x
Respuesta :
LammettHash
LammettHash
19-01-2017
[tex]\displaystyle\int\sec3x\tan3x\,\mathrm dx=\frac13\int\mathrm d(\sec 3x)=\frac13\sec3x+C[/tex]
or if you meant to use exponents,
[tex]\displaystyle\int\sec^3x\tan^3x\,\mathrm dx=\int\sec x\tan x\sec^2x(\sec^2x-1)\,\mathrm dx=\int(\sec^4x-\sec^2x)\,\mathrm d(\sec x)=\frac15\sec^5x-\frac13\sec^3x+C[/tex]
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