(f-g)(x) = 2x^2 - 5 - (3x+3)
(f-g)(x) = 2x^2 - 5 - 3x - 3
(f-g)(x) = 2x^2 - 3x -8
Answer:
(f-g)(x)= 2x^2-3x - 8
Step-by-step explanation:
If f(x)=2x^2-5 and g(x)=3x+3 find (f-g)(x)
(f-g)(x)= f(x) - g(x)
LEts subtract f(x)- g(x). plug in given f(x) and g(x)
Replace f(x) with 2x^2 -5 and g(x) with 3x+3
(f-g)(x)= f(x) - g(x) = (2x^2 -5) - (3x+3)
We have negative sign in between , distribute negative inside the second parenthesis
(f-g)(x)= 2x^2 -5 -3x - 3
Now combine like terms
(f-g)(x)= 2x^2-3x - 8
