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What is the equation of this circle in standard form?


(x−1)2+(y+1)2=5

(x−1)2+(y+1)2=25

(x+1)2+(y−1)2=25

(x+1)2+(y−1)2=5

What is the equation of this circle in standard form x12y125 x12y1225 x12y1225 x12y125 class=

Respuesta :

Answer:

I'll assume that all the (x and y) expressions are raised to the 2 power, not x2, as written:

E.g.:  (x+1)^2+(y−1)^2=25 not (x+1)2+(y−1)2=25

(x+1)^2+(y−1)^2=25  matches the graph.

Step-by-step explanation:

The center will be at (-1,1): (x+1)=0 and (y-1) = 0

(x+1)^2+(y−1)^2=25  matches the graph.

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