Solve the equation on the interval [0,2π). 7 sec x-7=0, x=?

[tex]\huge \bf༆ Answer ༄[/tex]
Let's solve ~
[tex]{ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:7 \sec(x) - 7 = 0[/tex]
[tex]{ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:7 \sec(x) = 7[/tex]
[tex]{ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \: \sec(x) = 7 \div 7[/tex]
[tex]{ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \: \sec(x) = 1[/tex]
[tex]{ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:x = 0[/tex]