PLEASE HELP!!! The areas of the squares adjacent to two sides of a right triangle are 29.25^2 units and 13^2 units. Find the length, x, of the third side of the triangle

Answer/Step-by-step explanation:
29.25^2 = 855.5625
each length there is 213.89
13^2 = 169
each length here is
42.25
So a^2+b^2 = c^2 (or how i look at it leg^2 + leg^2 = H^2)
42.25^2+213.89^2 = x^2
1785.06+45,748.9321 = x^2
47533.9921 = x^2
then you square eacj side to get x to be alone.
[tex]\sqrt{47533.9921} [/tex]= x
218.02 = x