Answer/Step-by-step explanation:
This is a 30-30-60 isosceles triangle.
So you haf it again and got your sides.
Your sides currently are: 8,[tex]\sqrt{80} [/tex], [tex]\frac{1}{2}x [/tex]
We could just use
Leg^2+leg^2 = H^2
[tex]8^{2} [/tex]+[tex]x^{2} [/tex]=[tex]\sqrt{80}^2 [/tex]
Subtraxt 8 squarded from each side
that leaves you with [tex]x^{2} [/tex]=16
you need x to not be squared so you square each side to get rid of it from x.
that makes it,
x=[tex]\sqrt{16} [/tex] and since 4*4 evenly multiplied is 16 x = 4
ANSWER =A: x=4
