Using the z-distribution, it is found that since the test statistic is greater than the critical value for the right-tailed test, this result shows that Zwerg can correctly follow this type of direction by an experimenter more than 50% of the time.
[tex]H_0: p \leq 0.5[/tex]
[tex]H_1: p > 0.5[/tex]
The test statistic is given by:
[tex]z = \frac{\overline{p} - p}{\sqrt{\frac{p(1-p)}{n}}}[/tex]
In which:
For this problem, the parameters are:
[tex]n = 48, \overline{p} = \frac{37}{48} = 0.7708, p = 0.5[/tex]
The value of the test statistic is:
[tex]z = \frac{\overline{p} - p}{\sqrt{\frac{p(1-p)}{n}}}[/tex]
[tex]z = \frac{0.7708 - 0.5}{\sqrt{\frac{0.5(0.5)}{48}}}[/tex]
[tex]z = 3.75[/tex]
Considering a right-tailed test, as we are testing if the proportion is greater than a value, with a significance level of 0.05, the critical value for the z-distribution is [tex]z^{\ast} = 1.645[/tex].
Since the test statistic is greater than the critical value for the right-tailed test, this result shows that Zwerg can correctly follow this type of direction by an experimenter more than 50% of the time.
To learn more about the z-distribution, you can take a look at https://brainly.com/question/16313918