The charge of the balloon is 3.36 x 10⁻¹⁷ C.
The number of excess electrons is 354 electrons.
The balloon gained electron since the electron is excess.
The given parameters:
- Number of excess electrons, n = 210 electrons
Charge of electron
The charge of one mole of an electron is approximately 1.6 x 10⁻¹⁹ C.
The charge of the balloon is calculated as follows;
[tex]-q = ne\\\\
-q = 210 \times 1.6 \times 10^{-19}\\\\
-q = 3.36 \times 10^{-17}\\\\
q = -3.36 \times 10^{-17 } \ C[/tex]
Number of excess electron
When the charge of the balloon become [tex]- 5.664 \times 10^{-17} \ C[/tex], the number of excess electrons is calculated as follows;
[tex]n = \frac{q}{e} \\\\
n = \frac{5.664 \times 10^{-17}}{1.6 \times 10^{-19}} \\\\
n = 354 \ electrons[/tex]
Thus, the balloon gained electron since the electrons are excess.
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