In a dihybrid cross involving pea plants heterozygous for two
traits (RrYy x RrYy), how many of the offspring will be
phenotypically yellow? Round (R) is dominant over wrinkled (r),
and Yellow (Y) is dominant over green (y).

a. 12/16
b. 9/16
c. 4/16
d. 3/16

Question

kms111005 kms111005

20-01-2022
Biology

contestada

In a dihybrid cross involving pea plants heterozygous for two
traits (RrYy x RrYy), how many of the offspring will be
phenotypically yellow? Round (R) is dominant over wrinkled (r),
and Yellow (Y) is dominant over green (y).

a. 12/16
b. 9/16
c. 4/16
d. 3/16

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luisvaschetto luisvaschetto · Answer 1 · 2022-02-03T10:33:10+01:00

The proportion of the offspring that will be phenotypically yellow is 12/16. It is classical mendelian genetics.

Mendelian genetics and phenotypic proportions

In diploid organisms, offspring receive two different gene forms or alleles, one from the mother and the other from the father.

An individual is homo-zygous when has the same allele for a given locus, whereas an individual is heterozygous when has different alleles for a given locus.

Dominance refers to the phenomena in which a dominant allele completely masks the phenotypic expression of the respective allele in heterozygous individuals.

Learn more about dominance here:

https://brainly.com/question/8448269

In a dihybrid cross involving pea plants heterozygous for two traits (RrYy x RrYy), how many of the offspring will be phenotypically yellow? Round (R) is dominant over wrinkled (r), and Yellow (Y) is dominant over green (y). a. 12/16 b. 9/16 c. 4/16 d. 3/16

Respuesta :

Mendelian genetics and phenotypic proportions

Otras preguntas

In a dihybrid cross involving pea plants heterozygous for two
traits (RrYy x RrYy), how many of the offspring will be
phenotypically yellow? Round (R) is dominant over wrinkled (r),
and Yellow (Y) is dominant over green (y).

a. 12/16
b. 9/16
c. 4/16
d. 3/16