Answer:
1.89 M
Explanation:
First calculate moles of NaOH
M = moles/Vol in L
moles = M x Vol in L
moles = 2.5 M x 0.0303 L
moles = 0.07575 moles
Also, the reaction between NaOH and H2SO4 is
2 NaOH + H2SO4 ----> Na2SO4 + 2 H2O
For every one mole of H2SO4, 2 moles of NaOH reacts.
So, for 0.07575 moles of NaOH, 0.037875 moles of H2SO4 will react.
Now, calculate molarity of H2SO4
M = moles / Vol in L
M = 0.037875 mol / 0.02 L
M = 1.89 M
