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Consider the synthesis of water as shown in Model 3. A container is filled with 10.0 g of H2 and 5.0 g of O2.
a. Which reactant (hydrogen or oxygen) is the limiting reactant in this case? Show your work. Hint: Notice that you are given reactant quantities in mass units here, not moles.
b. What mass of water can be produced? Show your work.
c. Which reactant is present in excess, and what mass of that reactant remains after the reaction is complete? Show your work.

Respuesta :

nuralfaqih

2H2 + O2 → 2H2O

First, we will find the moles :

n H2 = m H2 / Mr H2

n H2 = 10 / 2

n H2 = 5 mole

n O2 = m O2 / Mr O2

n O2 = 5 / 16

n O2 = 0.3125 mole

n H2 / coef. H2 > n O2 / coef. O2

So, O2 is the limiting reactant

The mass of water produced :

n H2O = (coef. H2O / coef. O2) • n O2

n H2O = (2/1) • 0.3125

n H2O = 0.625 mole

m H2O = n H2O • Mr H2O

m H2O = 0.625 • 18

m H2O = 11.25 gr

Excesses reactant :

n H2 = 5 - 0.625 = 4.375 mole

m H2 = n H2 • Mr H2

m H2 = 4.375 • 2

m H2 = 8.75 gr

mickymike92

Based on the equation of the reaction and the mass of reactants:

  • Oxygen, O₂ is the limiting reactant
  • mass of water produced is 5.625 g
  • hydrogen is the excess reactant and mass of hydrogen left is 9.375 g

What is the equation of the synthesis of water?

The equation of the synthesis of water is given below:

  • 2 H₂ + O₂ → 2 H₂O

From the equation of the reaction, 2 moles of hydrogen combines with 1 mole of oxygen to give two moles of water.

Moles of reactants:

Moles = mass/molar mass

molar mass of hydrogen gas = 2.0 g

molar mass of oxygen gas = 32.0 g

molar mass of water = 18.0 g

moles of H₂ = 10/2 = 5 moles

moles of O₂ = 5/32 = 0.15625 moles

  • Based on the mole ratio, oxygen (O₂) is the limiting reactant

The mass of water produced :

mole ratio of oxygen to water = 1 : 2

moles of water produced = 0.15625 moles × 2

moles of water = 0.3125 moles

mass of water produced = 0.3125 moles × 18 g/mol

  • mass of water produced = 5.625 g

Based on the mole ratio, the excess reactant is hydrogen.

Mass of hydrogen left = moles of hydrogen left × molar mass

moles of hydrogen left = 5 - 0.3125 = 4.6785 moles

mass of hydrogen left = 4.6785 × 2

mass of hydrogen left  = 9.375 g

Learn more about synthesis of water at: https://brainly.com/question/24189025

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