The probability of a random sample of 40 cans having a mean of 11.9 ounces of soda or less is 1.8%
Z score
Z score is used to determine by how many standard deviations the raw score is above or below the mean. It is given by:
[tex]z=\frac{x-\mu}{\sigma/\sqrt{n} }[/tex]
Where x is raw score, μ is mean, σ is standard deviation and n is sample size.
Given that:
σ = 0.3, n = 40, μ = 12, hence for x < 11.9:
[tex]z=\frac{11.9-12}{0.3/\sqrt{40} } =-2.1[/tex]
From the normal table, P(z < -2.1) = 1.8%
The probability of a random sample of 40 cans having a mean of 11.9 ounces of soda or less is 1.8%
Find out more on Z score at: https://brainly.com/question/25638875
