The strength of a magnetic field around a wire carrying a current of 20 A is 0. 004 T. What is the strength of the magnetic field if the current is changed to 40 A? 0. 002 T 0. 004 T 0. 006 T 0. 008 T.

Respuesta :

The strength of the magnetic field, if the current is changed to 40 A, is 0.008 T.

Magnetic Field:

The region in a space where the magnetic force is experienced by the particles is known as a magnetic field.

Given data:

The magnitude of current flow is, I = 20 A.

The strength of the magnetic field is, B = 0.004 T.

The expression for the magnetic field around a circular wire of radius r is,

[tex]B = \dfrac{\mu_{0} \times I}{2 \pi r}[/tex] ................................................(1)

here, [tex]\mu_{0}[/tex]  is the magnetic permeability of free space.

If the current becomes 40 A, then the new magnetic field is given as,

[tex]B' = \dfrac{\mu_{0} \times I'}{ 2 \pi r}[/tex] .................................................(2)

Taking the ratio of equation (2) and equation (1) as,

[tex]\dfrac{B'}{B} = \dfrac{I'}{I}\\\\ \dfrac{B'}{0.004} = \dfrac{40}{20}\\\\ B' = 0.008 \;\rm T[/tex]

Thus, we can conclude that the strength of the magnetic field, if the current is changed to 40 A, is 0.008 T.

Learn more about the magnetic field here:

https://brainly.com/question/7802337

Answer: 0.008 T

Explanation: I just took the exam

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