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The summit of mount Everest is at 29,029 feet. At this elevation the atmosphere pressure is 30 kPa or about 0.30 atm. What is the boiling point of water at the top of mount Everest

Respuesta :

The boiling point of water is 341.74K

Data Given;

  • height = 29,029 ft
  • pressure(p) = 30kpa = 0.30atm
  • T1 = 100^oC or 373K
  • H(vap) = 43653 kJ/mol

The formula to solve this problem is

[tex]ln(\frac{1}{p}) = \delta H/R (\frac{1}{T_1} - \frac{1}{T2}) [/tex]

We can solve for the final temperature here;

[tex]In(1/0.3) = 40653/8.314(\frac{1}{373}-\frac{1}{T_2}) [/tex]

[tex]ln(3.33) = \frac{4809.47}{T_2} - 13.108\\ T_2 = 341.72K = 69^0C[/tex]

solving for the boiling point of water (T2) at the top,

T2 = 341.72K = 69°C

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