The number of possible selections of the five donuts is; 21
The ample supply contains;
Since he wants to select 5 donuts, the orders could be;
Strawberry = 4, Chocolate = 1, Caramel = 0
or
Strawberry = 4, Chocolate = 0, Caramel = 1
or
Strawberry = 3, Chocolate = 2, Caramel = 0
e.t.c
Now, to solve this, Each option for Jamie is represented by an imaginary picture of five donuts (circles) and two bars (shelf separators).
Thus, the number of ways to select two spaces from 7 is;
7!/(5! × 2!) = 21
Read more about permutations and combinations at; https://brainly.com/question/11871015
