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Maggie rides her bike down a hill. She starts from rest and accelerates
at a rate of 2.5 m/s/s. If she reaches the bottom of the hill with a final
velocity of 38 m/s, how long is the hill?

Respuesta :

jeremiahkevinm

Answer:

288.8 m

Explanation:

v² = u² + 2as

  • v= final velocity= 38m/s
  • u = initial velocity = 0 m/s
  • a= acceleration=  2.5 m/s²
  • s = distance = ?

[tex]s = \frac{v^{2} - u^{2} }{2 a} \\\\\\s = \frac{38^{2} }{2* 2.5}\\\\ \\s = 288.8m[/tex]

salmaalblooshi73

Answer:

288.8 m

Explanation:

v² = u² + 2as

v= final velocity= 38m/s

u = initial velocity = 0 m/s

a= acceleration= 2.5 m/s²

s = distance = ?

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