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How would the expression x3 -3 sqrt 3 be rewritten using difference of cubes?
O A. (x- 13 )(x2-3x - 3)
O B. (x+ 3)(x + 13 x + 3)
C. (x - 13 )(x2 + 3x + 3)
O D. (x- vb)(x2 + v3 x+3)

Respuesta :

Neotheatre

Answer:

x^3 - (√3)^3

I'm not so sure since it's not even an option

Step-by-step explanation:

  • x^3 - 3√3 = x^3 - 3^1 × 3^(1/2)
  • from the laws of indices:
  • 3^1 × 3^(1/2) = 3^(1 + 1/2)
  • = 3^(3/2) which is the same as (√3)^3
  • so it could be written as x^3 - (√3)^3
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