Answer:
18000
Step-by-step explanation:
Given,
Back of lot of the trapezoid = 175
Front of lot of the trapezoid = 185
Length of lot of the trapezoid = 100
Therefore,
Area of the given trapezoid
[tex] = \frac{a + b}{2} c[/tex]
[tex] = \frac{175 + 185}{2} \times 100[/tex]
= 360 × 50
= 18000
Hence,
The required area of the given trapezoid is 18000 (Ans)
