The kinetic energy of the alpha particle is equal to: B.[tex]7.47 \times 10^{-13}\;J[/tex]
Given the following data:
- Velocity of alpha particle = [tex]1.5 \times 10^{7}\; m/s[/tex]
Scientific data:
- Mass of alpha particle = [tex]6.642 \times 10^{-27}\;kg[/tex]
To calculate the kinetic energy of the alpha particle:
Mathematically, kinetic energy is calculated by using this formula;
[tex]K.E = \frac{1}{2} MV^2[/tex]
Where:
- K.E is the kinetic energy.
- M is the mass of an object.
- V is the velocity of an object.
Substituting the given parameters into the formula, we have;
[tex]K.E = \frac{1}{2} \times 6.642 \times 10^{-27}\times (1.5 \times 10^{7})^2\\\\K.E = \frac{1}{2} \times 6.642 \times 10^{-27}\times 225 \times 10^{14}\\\\K.E =6.642 \times 10^{-27}\times 1.125 \times 10^{14}\\\\K.E =7.47 \times 10^{-13}\;J[/tex]
Read more on kinetic energy here: https://brainly.com/question/17081653
