8th-grade need help asap

[tex] - 2(5x + 3) \geqslant 14[/tex]
Divide both sides by -2
[tex] \frac{ - 2(5x + 3)}{ - 2} \leqslant \frac{14}{ - 2} \\ [/tex]
[tex]5x + 3 \leqslant - 7[/tex]
Subtract both sides 3
[tex]5x + 3 - 3 \leqslant - 7 - 3[/tex]
[tex]5x \leqslant - 10[/tex]
Divide both sides by 5
[tex] \frac{5x}{5} \leqslant \frac{ - 10}{5} \\ [/tex]
[tex]x \leqslant - 2[/tex]