Write the equation of a line that is perpendicular to x=5.

Write the equation of a line that is parallel to 4x+3y=1.

Write the equation of a line that is perpendicular to x-5y=2

Respuesta :

Write the equation of a line that is perpendicular to x=5.

x=5 is a straight line going through 5 on the x axis.  A line perpendicual to this will be any line parallel to the x axis.  This would mean y=[Any Number].  Pick what you want for [Any Number}, but I'll choose my lucky number, 6.

y =6

Write the equation of a line that is parallel to 4x+3y=1.

A parallel line have the same slope, so we can start by rewriting the equation in standard form of y=mx + b, where m is the slope and b the y-intercept (the value of y when x=0):

 3y = -4x + 1

 y = -(3/4)x + (1/3)

The slope is -(3/4), so the new line will also have the nsame slope.  Start by putting -(3/4) in the satandard format:

 y = -(3/4)x + b

In the absence of any other information, we are free to pick whatever value we want for b, as long as it is not 1.  I'll choose . . .

y = -(3/4)x + 6

Write the equation of a line that is perpendicular to x-5y=2

As before, rewrite into standard form:

-5y = -x + 2

y = (1/5)x + 2

A perpendicular equation will have a slope that is the negative inverse of the reference line.  The negative inverse of (1/5) is -5.  Now we have:

    y = -5x + b

Since we aren't given any addition information, we can pick any b we want.  

   y = -5x + 6

See the attached graph.

Ver imagen rspill6
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