Determine the following probabilities. Enter your final answers as reduced fractions. Two coins are flipped. Find the probability that the first coin land on heads and the second coin lands on heads. Two cards are drawn from a deck of 52 cards. The first card is replaced before drawing the second card. Find the probability that the first card is hearts and the second card is a Jack. A single digit between 0 and 9 is randomly chosen, and a single letter from A to Z is randomly chosen. Find the probability that the number is 3 and the letter is a consonant. Two dice are rolled. Find the probability that first die lands on an even number and the second die is less than 3 .

Respuesta :

Probabilities are used to determine the chances of events

(a) Coins

In a coin, the probability of the likely outcomes in each flip are:

Head = 1/2

Tail = 1/2

So, the probability that the first lands on head, while the second lands on tail is:

[tex]\mathbf{Pr = \frac 12 \times \frac 12}[/tex]

[tex]\mathbf{Pr = \frac 14}[/tex]

The probability that the first lands on head, while the second lands on tail is 1/4

(b) Deck of cards

There are 52 cards in a deck, 13 of which are hearts while 4 are jack.

The probability that the first card is heart is 13/52

The probability that the second card is jack is 4/51

So, the probability that the first selected card is heart, while the second is jack is:

[tex]\mathbf{Pr = \frac{13}{52} \times \frac{4}{51}}[/tex]

[tex]\mathbf{Pr = \frac{1}{51}}[/tex]

The probability that the first selected card is heart, while the second is jack is 1/51

(c) Digits and Letters

There are 10 digits between 0 and 9, so the probability of selecting 3 is 1/10.

There are 21 consonants, so the probability of selecting a consonant is 21/26

So, the probability of selecting 3 and a consonant is:

[tex]\mathbf{Pr = \frac{1}{10} \times \frac{21}{26}}[/tex]

[tex]\mathbf{Pr = \frac{21}{260}}[/tex]

The probability of selecting 3 and a consonant is 21/260

(d) Dice

There are 3 even numbers on a die; so the probability of landing on an even number is 3/6

There are 2 numbers less than 3 on a die; so the probability of landing on a number less than 3 is 2/6

So, the probability of landing on an even number and a number less than 3 is:

[tex]\mathbf{Pr = \frac 36 \times \frac 26}[/tex]

[tex]\mathbf{Pr = \frac 16}[/tex]

The probability of landing on an even number and a number less than 3 is 1/6

Read more about probabilities at:

https://brainly.com/question/11234923

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