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A 600 kg elevator initially moving upward undergoes motion represented by the
velocity vs time graph shown. Calculate the force of tension supporting the
elevator. (Enter your answer as four significant figures without units or spaces.
Ex) If the force=1598.3 N enter "1598") *
velocity
(m/s)
7
6
ET
5
4
3
2
1
time
(5)
0
1
2
3
4
5
6
7

A 600 kg elevator initially moving upward undergoes motion represented by the velocity vs time graph shown Calculate the force of tension supporting the elevato class=

Respuesta :

oladayoademosu

The force of tension supporting the elevator is 400.0 N

To find the force of tension supporting the elevator, we need to find the acceleration of the elevator from the gradient of the graph.

So, a = Δv/Δt = (v₂ - v₁)/(t₂ - t₁) where v₁ = 2 m/s, t₁ = 0 s, v₂ = 6 m/s and t₂ = 6 s

So, a = (6 m/s - 2 m/s)/(6 s - 0 s)

a = 4 m/s ÷ 6 s

a = 2/3 m/s²

a = 0.67 m/s²

So, the force of tension on the elevator, T = ma where m = mass of elevator = 600 kg and a = acceleration of elevator = 2/3 m/s².

So, T = ma

T = 600 kg × 2/3 m/s²

T = 400 N

So, the force of tension supporting the elevator is 400.0 N

Learn more about tension here:

https://brainly.com/question/15323831

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