You are observing a population of squirrels that have red or black fur. Coat color in these squirrels is determined by one gene with two alleles, where red is dominant to black. In your population, you count 100 squirrels and find 84 red squirrels and 16 black squirrels. What is the frequency of the black fur allele

Respuesta :

Assuming that the diallelic gene, which codes for fur color, express complete dominance, and following H-W equilibrium, the frequency of the black fur allele is f(r) = 0.4

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Available data:

  • Single, diallelic gene coding for fur color
  • Red is the dominant trait
  • Black is the recessive trait
  • Total number of squirrels, N = 100
  • 84 animals are red
  • 16 animals are black

We need to calculate the frequency of the recessive allele.

We will say that,

  • R is the dominant allele that codes for red
  • r is the recessive allele that codes for black

We will assume complete dominance, where R completely masks the expression of r allele, so heter0zyg0us individuals express the dominant trait.

Following Hardy-Weinberg equilibrium, the allelic frequencies in a locus are represented as p and q. Assuming a diallelic gene,  

  • p is the frequency of the dominant allele,  
  • q is the frequency of the recessive allele.  

The genotypic frequencies after one generation are  

  • (H0m0zyg0us dominant genotypic frequency),  
  • 2pq (Heter0zyg0us genotypic frequency),  
  • (H0m0zyg0us recessive genotypic frequency).  

So, if we have the genotypic frequency of the recessive phenotype (black fur) we can get the allelic frequency.

  • We know that there are 16 black suirrels
  • And we know that the total number of individuals in the population is 100

So the frequency of the black squirrels -F(rr)- in the population is,

F(rr) = q² = 16/100 = 0.16

Now, by taking the root square of this value, we will get the allelic frequency, f(r).

  • F(rr) = q² = 0.16
  • f(r) = q = √q² = √0.16 = 0.4

The frequency of the black fur allele is f(r) = 0.4.

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