Respuesta :
Assuming that the diallelic gene, which codes for fur color, express complete dominance, and following H-W equilibrium, the frequency of the black fur allele is f(r) = 0.4
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Available data:
- Single, diallelic gene coding for fur color
- Red is the dominant trait
- Black is the recessive trait
- Total number of squirrels, N = 100
- 84 animals are red
- 16 animals are black
We need to calculate the frequency of the recessive allele.
We will say that,
- R is the dominant allele that codes for red
- r is the recessive allele that codes for black
We will assume complete dominance, where R completely masks the expression of r allele, so heter0zyg0us individuals express the dominant trait.
Following Hardy-Weinberg equilibrium, the allelic frequencies in a locus are represented as p and q. Assuming a diallelic gene,
- p is the frequency of the dominant allele,
- q is the frequency of the recessive allele.
The genotypic frequencies after one generation are
- p² (H0m0zyg0us dominant genotypic frequency),
- 2pq (Heter0zyg0us genotypic frequency),
- q² (H0m0zyg0us recessive genotypic frequency).
So, if we have the genotypic frequency of the recessive phenotype (black fur) we can get the allelic frequency.
- We know that there are 16 black suirrels
- And we know that the total number of individuals in the population is 100
So the frequency of the black squirrels -F(rr)- in the population is,
F(rr) = q² = 16/100 = 0.16
Now, by taking the root square of this value, we will get the allelic frequency, f(r).
- F(rr) = q² = 0.16
- f(r) = q = √q² = √0.16 = 0.4
The frequency of the black fur allele is f(r) = 0.4.
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