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Jessica and Laura are shopping for new clothes at a store that is going out of business. The different brands of shirts are all the same price, and the same goes for pants. At the store, Jessica purchases 3 shirts and 4 pairs of pants for a total of $90. Laura purchases 4 shirts and 2 pairs of pants for a total of $70.

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adioabiola

Given Jessica and Laura's expenditure on shirts and pants, the equation to solve for the price of each shirts and pants is:

3s + 4p = 90

4s + 2p = 70

Let

Cost of each shirts = s

Cost of each pants = p

Jessica:

3s + 4p = 90 (1)

Laura:

4s + 2p = 70 (2)

Multiply (2) by 2

8s + 4p = 140 (3)

8s + 4p = 140 (3)3s + 4p = 90 (1)

Subtract (1) from (3) to eliminate p

8s - 3s = 140 - 90

5s = 50

s = 50/5

s = $10

substitute s = 10 into (1)

3s + 4p = 90 (1)

3(10) + 4p = 90

30 + 4p = 90

4p = 90 - 30

4p = 60

p = 60/4

p = $15

Therefore, the cost of each shirts is $10 and the cost of each pants is $15

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