The given box has the shape of a cuboid, since its height is greater than its width. Thus, the maximum volume for such box is 11200 [tex]in^{3}[/tex].
The volume of an object is a measure of it containing capacity. Since the given box has a taller height than its width, then it has the shape of a cuboid. The volume of a cuboid is given as:
volume = length x width x height
= area x height
Given that the sum of the perimeter of its base and its height is not more than 108 inches, we can say; let the sides of the square base be represented by l and its height by h.
Then;
4l + h = 108
Therefore, maximum volume for the box can be attained when l = 20 inches and h = 28 inches.
So that;
4(20) + 28 = 80 + 28
= 108 inches
Thus;
maximum volume = area of the square base x height
= 400 x 28
maximum volume = 11200 [tex]in^{3}[/tex]
The maximum volume for such a box would be 11200 [tex]in^{3}[/tex].
Visit: https://brainly.com/question/20463446
